Warning: Uber-vain post ahead.
Only in this crazy-wonderful-Net-frantic world do some websites come into your life and leave a dent. Yes, some will just intentionally waste your time, but well, there are a few sites that I’m thankful I stumbled upon. I remember running across this page which featured an ingenious family’s take on annual family portraits (check it out at http://zonezero.com/magazine/essays/diegotime/time.html) — each year they take id photos of themselves and now they have 30 years’ worth of photos/hairstyles to reminisce. This got me thinking, ‘why don’t I do the same and have a photo shoot every year on my birthday?’. What did I tell you — uber-vain, right?
I bought the first discounted photo-shoot package I saw on one of my beloved voucher sites, but I never got around to taking the shoot during my last birthday. The new year rolled around, and I didn’t get to book either. Finally, on this characteristically lazy weekend, I decided to haul my butt off the couch and finally get that shoot done.
What I didn’t expect was how fun it would be. It brought me back to the grade-school/high-school days when digital cams were yet unheard of, and trips to Galleria meant movie+lunch+neoprint+studiopic shoot. I remember cringing at my smile whenever we got the prints from the studio, but today at DeCharacter Image’s studio (it’s located on Purvis St. near Raffles Hotel), Dana (the stylist — sashyaaaal…) and Kyaw (the photographer. I repeat — sashyaaaal…) put me in so much ease that I only remembered how awkward a shoot should be after the shoot. So kudos, Dana & Kyaw! 🙂
If you’ve read up to here and you’re not puking yet, you may want to check out the other pics from the shoot — https://picasaweb.google.com/ishgagno/201102Me# .
(If my sisters are reading this — since Ondoy washed most of our childhood pics away and we literally are oceans apart now, what do you say to making our own yearly timeline? It’ll be fun to show it to our kids 30 years from now. 🙂 Let’s have it every Christmas, what do you guys think?)